Minimum Marks In JEE Mains To Qualify For JEE Advanced

JEE Main Cutoff for Advanced 2025 is released by the NTA. The Minimum Marks In JEE Mains To Qualify For JEE Advanced for General is 86 marks, EWS is 84 marks, OBC is 82, SC is 60 and PwD is 0.0018. Check detailed Minimum Marks here. [{ "selector": ".qqpbw-a", "duration": "500ms", "fill": "forwards", "delay": "0ms", "keyframes": [ {"offset": 0, "transform": "translateX(-360px)", "opacity": "1", "visibility" :"visible" }, {"offset": 1, "transform": "translateX(0)", "opacity": "1", "visibility" :"visible"} ] }, { "selector": ".zxcbm-a", "duration": "500ms", "fill": "forwards", "delay": "0ms", "keyframes": [ {"offset": 0, "transform": "translateX(calc(360px - 0px))", "opacity": "1", "visibility" :"visible"}, {"offset": 1, "transform": "translateX(0)", "opacity": "1", "visibility" :"visible"} ] }]

JEE Main Cutoff for Advanced (General)

1: 2024: 95.0 percentile (~93.2362181 marks) 2: 2023: 90.7 percentile (~75 to 85 marks) 3: 2022: 88.4 percentile (~70 to 80 marks) 4: 2021: 87.9 percentile (~70 to 80 marks)

Expected JEE Main Cutoff for Advanced

1: General - 93 to 95 Percentile 2: OBC - 91 to 93 Percentile 3: EWS - 91 to 93 Percentile 4: SC - 82 to 86 Percentile 5: ST - 73 to 80 Percentile

How Many Students Qualify JEE Advanced?

Top 25,000 candidates who score above the JEE Main cutoff 2025 are eligible to appear for JEE Advanced.

JEE Main Cutoff for Advanced - CSE

1: IIT Bombay - 68 2: IIT Delhi - 116 3: IIT Madras - 159 4: IIT Kanpur - 252 5: IIT Kharagpur - 415

JEE Main Cutoff for Advanced - CE

1: IIT Bombay: Rank 1150 to 1200 2: IIT Delhi: Rank 1500 to 1600 3: IIT Kanpur: Rank 1600 to 1700 4: IIT Madras: Rank 1600 to 1700 5: IIT Kharagpur: Rank 1800 to 1900 6: IIT Roorkee: Rank 1800 to 1900

JEE Main Cutoff for Advanced - EE

1: IIT Bombay: Rank 320 to 350 2: IIT Delhi: Rank 550 to 600 3: IIT Kanpur: Rank 500 to 550 4: IIT Madras: Rank 500 to 600 5: IIT Kharagpur: Rank 650 to 700 6: IIT Guwahati: Rank 650 to 700